x/x-8+7=8/x-8
2006-10-17 01:53:10 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It's hard to tell, because I suspect you haven't formatted this problem correctly.
If (x - 8) is the denominator of two fractions, then it's as follows.
[x / (x - 8)] + 7 = [8 / (x - 8)]
x + 7(x - 8) = 8
x + 7x - 56 = 8
8x = 64
x = 8
In the second line, I just multiplied every term by (x - 8). However, the answer I got does not work in the original equation, because it gives a denominator of x - 8 = 8 - 8 = 0, which is impossible. That means there is no answer.
If the denominator is only x, you just treat 7 algebraically.
(x / x) - 8 + 7 = (8 / x) - 8
1 - 8 + 7 = (8 / x) - 8
8 = 8 / x
x = 1
2006-10-17 02:07:38 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
x/x = 1, so the left side becomes 1-8+7 or 0.
now 0 = 8/x -8 so 8/x = 8, so x=1
2006-10-17 14:48:20 · answer #2 · answered by davidosterberg1 6 · 0⤊ 0⤋
Let's rewrite the equation because I think it should look like this:
x/(x-8)+7=8/(x-8).
Now multiply each side by (x-8). You will get :
x+7(x-8)=8
x+7x-56=8
8x=8+56
8x=64
x=64/8
x=8
Your question should be: how do I simplify the equation?
As you have seen, we eliminated the denominator (x-8) by multiplying each term in the equation by (x-8). That way the (x-8) in the denominator is cancelled out and disappears. After you have done that, the rest is "easy" as one answerer said. But if not, please come back with another question on this problem. I'll be glad to help.
2006-10-17 09:14:47 · answer #3 · answered by tul b 3 · 0⤊ 0⤋
Do you mean should you calculate x/x - 8 first
or 8 +7 first or what?
Anyway if x = 1 the formula works.
See your maths teacher for further assistance.
2006-10-17 09:02:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
x/x equals 1...always....so:
1-8+7=8/x-8..so:
-7+7=8/x-8...so:
0=8/x-8...which leaves:
8/x=8...so x = 1....that means ...u do nothing with the seven.. it cleares itself....
2006-10-17 09:09:44 · answer #5 · answered by Pietie 1 · 0⤊ 0⤋
you mean x/(x-8) + 7 = 8/(x-8)
take 7 to the right and 8/(x-8) to the left
x/(x-8) -8/(x-8) = -7
or (x-8)/(x-8) = -7
or 1= -7
so it is inconsistant
if (x-8) is not in denominator
1 -8 + 7 = 8/x -8
or 8 = 8/x or x = 1
2006-10-17 08:59:30 · answer #6 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
x/(x-8)+7=8/(x-8)
x/(x-8) - 8/(x-8)= -7
(x-8)/ (x-8)= -7
1= -7????????????
i think somethink wrong in Q
check it out and give Qproperly
2006-10-17 09:07:29 · answer #7 · answered by . 3 · 0⤊ 0⤋
x/[x-8]+7=8/[x-8]
x+7[x-8]=8
x+7x-56=8
8x=64
x=8
2006-10-17 10:06:09 · answer #8 · answered by openpsychy 6 · 0⤊ 0⤋