4x^2 + 36xy =81y^2?

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2006-10-16 18:22:23 · 4 answers · asked by moe 1 in Science & Mathematics ➔ Mathematics

4 answers

4x^2+36xy+81y^2
i think you copied the sum wrong
(2x)^2+2(2x)(9y)+(9y)^2
=(2x+9y)^2
=>(2x+9y)(2x+9y)

2006-10-16 18:27:43 · answer #1 · answered by raj 7 · 0⤊ 0⤋

4x^2 + 36xy = 81y^2
4x^2 - 36xy + 81y^2 = 0
(the q is wrong it shld hv been 4x^2 + 81y^2 = 36xy)

is of the format a^2 + b^2 - 2ab -- eq 1

thus here a = 2x , b= -9y

The above eq 1 deduces to (a - b) (a + b)

thus resulting in

(2x - 9y) (2x + 9y)

2006-10-17 08:11:36 · answer #2 · answered by nanduri p 2 · 0⤊ 0⤋

x=1 and y=2.14

2006-10-17 01:28:12 · answer #3 · answered by Cycleogical 2 · 0⤊ 0⤋

What is your question?

2006-10-17 09:34:36 · answer #4 · answered by tul b 3 · 0⤊ 0⤋