thanks
2006-10-16 18:19:24 · 5 answers · asked by rockoutdude85@sbcglobal.net 2 in Education & Reference ➔ Homework Help
3y^2- 5y+ 8 = 3y^2+3y- 8y+ 8 = 3y(y-1) - 8 (y-1) =(y- 1) (3y-8)
2006-10-16 18:37:25 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Use parenthesis. It would really help.
Is the question (3y^2)-(5y)+(8)
or is it (3y)^(2-5y+8).
I assume it's (3y^2)-(5y)+(8)
2006-10-17 01:25:34 · answer #2 · answered by Ryan 2 · 0⤊ 0⤋
Hey, dude - if you post all your math problems here and get people to do them for you, what are you going to do when test time comes? Will your teacher let you bring your laptop into class and post the test questions too?
People who just give you the answers aren't really helping you, even if they think they are.
2006-10-17 01:27:55 · answer #3 · answered by Judy 7 · 0⤊ 1⤋
a=3;b=-5 and c=8
use the quadratic formula
y=[-(-5)+/-rt(25-96)]6
=[5+/-rt(-71)]/6
=[5+/-ity71]/6
2006-10-17 01:23:39 · answer #4 · answered by raj 7 · 0⤊ 0⤋
K....
2006-10-17 01:22:18 · answer #5 · answered by noobgirl 2 · 0⤊ 1⤋