A skier has a horizontal velocity of 104.5 km/h at the end of a ramp, before a horizontal surface (the velocity is where the ramp and ground meet). The snow on both the horizontal surface and the ramp produces a coefficient of friction of .12 with the skis. If the initial velocity with which the skier started is twice the velocity of the final velocity (at the end of the horizontal surface), what distance will the skier travel overall?
I think that I need to divide out the ramp and horizontal surface into two parts, but I don't know what to do after that. Do I use Net Work is equal to change in Kinetic Energy or do I use Work of Friction is equal to Change in Kinetic Energy + Change in Potential Energy?
The skier starts off at the top of the ramp. At the bottom of the ramp, his speed is 104.5 km in the horizontal direction.
The distance I need to find is how far the skier travels from the beginning of the ramp to how ever far he travels across the horiontal surface.
2006-10-16 17:18:28 · 1 answers · asked by shayonsaleh 2 in Education & Reference ➔ Homework Help
http://en.wikipedia.org/wiki/Coefficient_of_friction
2006-10-16 17:40:31 · answer #1 · answered by Surya M. 3 · 0⤊ 0⤋