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I'm a five-digit number containing each of the five odd digits. I'm not dividible by 5. The 1 is neither next to the 3 nor the 7; the 3 is next to the 5. I neither start with nor end in 9 or 1. The middle digit is not prime or composite. The sum of the first two digits is less than the sum of the last two digits. Who am I?

2006-10-16 17:17:24 · 5 answers · asked by heythere 2 in Education & Reference Homework Help

5 answers

35197
because...
By definition, every integer greater than one is either a prime number or a composite number. The numbers zero and one are considered to be neither prime nor composite.

So - 3 plus 5 is 8 which is greater than 9 plus seven which is 16...and the 3 is next to the 5. And lastly it is not divisible by 5 - this was the first one I came up with but I thought one was prime...looked up composite and found out that it is not..

:o)

2006-10-16 17:18:22 · answer #1 · answered by Anonymous · 0 2

It's 35197

2006-10-16 17:26:08 · answer #2 · answered by sunshine 4 · 0 0

35197

2006-10-16 17:43:35 · answer #3 · answered by butrcupps 6 · 0 0

35197 maybe?

2006-10-16 17:21:25 · answer #4 · answered by L.J. 4 · 1 0

35197???

2006-10-16 17:26:14 · answer #5 · answered by ? 2 · 1 0

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