at noon on a certain day, the petri dish is completely covered (100%). At what times (nearest second) was the percentage of the plate covered by the bacteria:
a) 25%
b) 5%
c) 1%
2006-10-16 16:48:21 · 5 answers · asked by thebeautiful08 1 in Science & Mathematics ➔ Mathematics
Let,
i = initial bacteria count,
f = final bacteria count,
t = minutes
then
i * 2^(t/10) = f
2^(t/10) = f / i
(t/10) * ln(2) = ln (f / i)
t = 10 * ln (f / i) / ln (2) = 14.427 * ln (f / i)
a) i/f = 1/4, f/i = 4 so t = 20 mins
b) i/f = 1/20, f/i = 20, so t = 43.22 mins = 43 mins, 13 secs
c) i/f = 1/100, f/i = 100 so t = 66.44 mins = 66 mins, 26 secs
You can subtract those results from noon to get the answers
2006-10-16 17:24:11 · answer #1 · answered by Joe C 3 · 0⤊ 1⤋
at noon 100% full.
At 11:50 half full
At 11:40 25% full.
At 11:30 12.5% full
At 11:20 6.25 % full
At 11:10 3.125%full
At 11:00 1.0625% full.
2006-10-17 03:31:40 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The form of micro organism doubles each 10 minutes. There are sixteen*60 minutes in 60 hours, that's ninety six communities of 10 minutes. Then, the form of micro organism is doubled ninety six cases. the in simple terms top form of micro organism is two*2*2* . . .. (ninety six cases) that's 2^ninety six
2016-11-23 15:34:21 · answer #3 · answered by tenuta 4 · 0⤊ 0⤋
X = percentage
10min * ln(1/X)/ln(2)
a) 1140
b)
c)
2006-10-16 17:02:41 · answer #4 · answered by feanor 7 · 0⤊ 0⤋
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2006-10-16 16:56:30 · answer #5 · answered by mary S 1 · 0⤊ 1⤋