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How many milliliters of 0.327 M H2SO4 are required to neutralize completely 77.5 mL of 0.143 M Al(OH)3?

How many milliliters of 0.327 M H2SO4 are required to neutralize completely 77.5 mL of 0.143 M Al(OH)3

2006-10-16 16:45:02 · 1 answers · asked by bkowner2003 2 in Science & Mathematics ➔ Chemistry

1 answers

3 * 0.143 * 77.5 = 2 * 0.327 * X

X = 50.84

2006-10-16 16:54:59 · answer #1 · answered by feanor 7 · 0⤊ 0⤋

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