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Find All the numbers such that the sum of
twice the number and 18 is greater than
or equal to five times the number
2006-10-16 16:12:43 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
this is an inequality type question.
2x+18>=5x
-2x -2x
----------------
18>=3x now divide each side by 3
6>=x
so it is true for all numbers less than or equal than 6
hope this helps
matty
2006-10-16 16:20:16 · answer #1 · answered by Matty G 2 · 0⤊ 0⤋
"sum of twice the number and 18" = 2N + 18
N is the "number"
"five times the number" = 5N
2N + 18 < OR = 5N
18 < OR = 5N-2N
18 < OR = 3N
18/3 < OR = 3N/3
6 < OR = N
rewriting this we have...
N > OR = 6
So your answer is all the numbers greater than 6 including 6.
2006-10-16 16:20:23 · answer #2 · answered by naike_10021980 2 · 0⤊ 0⤋
2x + 18 is greater than or equal to 5x
the number (x) is less than or equal to 6
2006-10-16 16:18:32 · answer #3 · answered by Anonymous · 0⤊ 0⤋
2x+18 is greater than or equal to 5x
Subtract 2x from both sides to get
18 is greater than or equal to 3x
Divide each side by 3 to get
6 is greater than or equal to x
So x would have to be the numbers equal to or less than 6.
2006-10-16 16:23:58 · answer #4 · answered by G.V. 6 · 0⤊ 0⤋
2*x + 18 >= 5*x
18 >= 3*x
6 >= x
2006-10-16 16:22:18 · answer #5 · answered by Math geek 3 · 0⤊ 0⤋