An 1900 kg car is moving to the right at a constant speed of 1.80 m/s.
(a) What is the net force on the car?
____N to the right
(b) What would be the net force on the car if it were moving to the left?
___N to the left
how do you solve this?
2006-10-16 15:49:03 · 5 answers · asked by tingerpoo 2 in Science & Mathematics ➔ Physics
If you are ignoring friction forces such as air resistance and wheel friction, then the net force on the car is 0 Newtons no matter what direction you are going.
Why? This is true because F = ma. In a constant velocity case a = 0 (acceleration). If you add in friction it becomes F = ma + F_fr, which would give you a positive value for F. In this case, the question does not give you enough information, so since it is probably homework, you do not have to account for F_fr
2006-10-16 15:51:05 · answer #1 · answered by polloloco.rb67 4 · 0⤊ 0⤋
I think this is a trick question. Force is mass times acceleration. Traveling in a horizontal path at a constant speed yields no acceleration. The only force acting on the car in either left or right direction would be the mass times gravity force. 1900kg*9.8m/s^2 would be both answers.
2006-10-16 22:56:51 · answer #2 · answered by ybot84 2 · 0⤊ 0⤋
a f=ma so 1900kg times 0m/s^2 (bc its moving at a contstant velocity) so force =0N to the right (would help if i had distance traveled bc then i could find acceleration using a=v/t
um... it would be the same... lol just going in different directions
2006-10-16 22:53:59 · answer #3 · answered by scoot 2 · 0⤊ 0⤋
You to solve this using potential and kinetic energy or using the conservation of energy.
Consider this formula: Kinetice Energy=Σmv^2
E=1900(1.8)^2
E= 6156 Newton
Therefore if it is moving to the right E=+6156 N and if moving to the left it is E=-6156
2006-10-16 23:10:08 · answer #4 · answered by Dennis T 2 · 0⤊ 1⤋
if the velocity is constant then the acceleration is zero in any direction
2006-10-16 22:51:21 · answer #5 · answered by Greg G 5 · 0⤊ 0⤋