Find a Polynomial; Zeros: -3, multiplicity 2: 1, mult. 1; 5, mult 3; degree = 6?

Answer 1

(x+3)^2((x-1)((x-5)^3

Answer 2

If r is a root of a polynomial then x-r is a factor.
So your answer is
(x+3)^2 *(x-1)*(x-5)^3. Notice that the degree of
the first factor is 2, the degree of the second factor is 1
and the degree of the third factor is 3, making
the total degree 6.

Answer 3

i'm guessing you opt to locate a polynomial that has those roots. if so: record right here roots one time for each multiplicity, and make a element from them: x = -3 <--> x + 3 = 0 x = -3 <--> x + 3 = 0 x = -a million <--> x + a million = 0 x = 2i <--> x - 2i = 0 because all the coefficients are real, the roots could are available in complicated conjugates, so: x = -2i <--> x + 2i = 0 because you have all 5 aspects, merely merely multiply the climate at the same time: (x + 3)(x + 3)(x + a million)(x - 2i)(x + 2i) (x^2 + 6x + 9)(x + a million)(x^2 + 4) (x^3 + 7x^2 + 15x + 9)(x^2 + 4) x^5 + 7x^4 + 19x^3 + 37x^2 + 60x + 36