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5ax + 10ay - 20az

2006-10-16 13:03:22 · 2 answers · asked by sp00nkitty 1 in Education & Reference Homework Help

2 answers

Factor out your a's:
a(5x+10y+20z)
Then, since every coefficient is divisble by five, factor out a five:
5a(x+2y+4z)

2006-10-16 13:06:04 · answer #1 · answered by Tori 2 · 1 1

5ax+10ay-20az=0
5ax+10ay-20az=0 :a
5x+10y-20z

so then
5x= -10y+20z :5
x= -2y+4z
and
10y= 20z-5x :10
y=2z-1/2x
and
-20z= -5x-10y : (-20)
z=1/4x+1/2 y

Thats how far I get it...

2006-10-17 04:51:36 · answer #2 · answered by JoJoNa 2 · 0 0

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