Confused & Need help with chem!! -- Max wavelength -- removing electron for a hydrogen atom -- ??

Question

What is the maximum WAVELENGTH of light capable of REMOVING AN ELECTRON for a HYDROGEN ATOM if n=5?

Answer 1

What fun !

The first ionisation energy of hydrogen is 1312 kJ/mol. (Look it up !) The potential energy of any level, n, in the hydrogen atom is 1312 kJ/mol/n^2 .

So, for the fifth level (n = 5), potential energy = 52.48 kJ/ mol.
That's the energy it would take to remove the electron.

That's for a mole, so for one, divide by Avogadro's number.
= 8.7176 x 10^-23 kJ
= 8.7176 x 10-20 J

The equation for the energy (E) of a photon of light is

E = hc/lambda.

Rearranged to solve for lambda (wavelength)

hc/E = (6.63 x 10^-34 J) (3.00 x 10^8 m/s)/ 8.7176 x 10-20 J)

= 2.28 x 10-6 m

Answer 2

use the formula to artwork out the energies at n=a million and n=4. the version is the capability that is going to produce the easy photon. you're able to desire to grasp capability = h * frequency to be having questions like this, so in simple terms divide E by utilising h (Planck's consistent) and there you bypass.