Can someone help me with this circular motion problem?

Question

A 9.5 kg monkey is hanging by one arm from a branch and is swinging on a vertical circle. As an approximation, assume a radial distance of 85 cm between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of 2.2 m/s.

(a) Find the magnitude of the centripetal force acting on the monkey.
N
(b) Find the magnitude of the tension in the monkey's arm.
N

I got part A right with 54.1

Now for part b, I did 54.1^2 + 93.1^2 (I got that number from 9.5 * 9.8) = T^2 but that is wrong.. what is the correct way to do part b?

I submitted the answer 93 online and it appears to be incorrect :-/

132 doesn't appear to be correct either.

Shouldn't 9.5*2.2^2*.85 = 39.083 be )9.5 * 2.2^2)/.85 = 54.1?

Answer 1

Centripetal force = mv^2/R
mass of monkey = 9.5kg
R = 0.85m
v = 2.2m/s
C.F. = 9.5x(m/s)x(2.2m/s)^2/0.85m 54.1N
Tbot = m(v^2/R + g)
Tbot = 9.5kg(2.2^2/0.85 + 9.8m/s^2)
Tbot = 147.2N

Answer 2

Centrifugal force is mv^2/r. The monkey has a mass of 9.5 kg, is swinging at v=2.2 m/s and r is 0.85 meters, so the force is 9.5*2.2^2*.85 = 39.083 Newtons. The tension is just the sum of the centrifugal force plus the weight of the monkey. Since the acceleration of Earth's gravity is 9.8 m/s^2, the monkey weighs 9.8*9.5=93.1 Newtons. Tension is 93.1+39.083=132.183 Newtons. I would round it to 132.