A rock dropped on the moon will increase its speed from 0 m/s (its starting speed when first dropped) to 4.9 m/s in about 3 seconds. What value do you calculate for the acceleration of gravity on the moon?
A. 4.9 m/s2 up
B. 1.63 m/s2 down
C. 9.8 m/s2 down
D. 14.7 m/s2 up
2006-10-16 10:23:39 · 3 answers · asked by bombshellimage 1 in Science & Mathematics ➔ Physics
B.
4.9 m/s velocity change divided by the 3 seconds it took is 1.633.. m/s^2 in the down direction.
2006-10-16 11:07:38 · answer #1 · answered by campbelp2002 7 · 0⤊ 0⤋
Use v = u +gt
Where v = final velocity
u = initial velocity = 0m/s
t = time interval
4.9m/s = 0 + gx3s
g = 4.9/3 = 1.63m/s^2
so B is the correct answer
2006-10-16 11:29:55 · answer #2 · answered by quark_sa 2 · 0⤊ 0⤋
it is B
my teacher told me that
2006-10-16 10:28:36 · answer #3 · answered by 7 · 0⤊ 0⤋