How do you write 4 squared times 2 to the fourth as a product of factors? What is the evaluation of the expression?
2006-10-16 10:08:42 · 5 answers · asked by crash 3 in Science & Mathematics ➔ Mathematics
4^2 * 2^4
= (2*2)^2 * 2^4
= 2^2 * 2^2 * 2^4
= 2^8
2006-10-16 10:15:41 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
4² * 2^4 (sorry, can't write a superscript 4 on here :) )
The exponent tells you how many of that factor to use. So the expression above equals:
4 * 4 * 2 * 2 * 2 * 2
which you can multiply out on your own, I trust. It isn't 64, though. :) Hope that helps!
2006-10-16 17:11:40 · answer #2 · answered by Jay H 5 · 0⤊ 0⤋
4 * 2^4
= 2^2 * 2^4
= 2^6
=64
2006-10-16 17:12:03 · answer #3 · answered by bequalming 5 · 0⤊ 1⤋
[4²] * [2^4]
= [4*4] * [2*2*2*2]
= [2*2]*[2*2] * [2*2*2*2] (same as saying 2^8)
= 256
To Jay H: How do you type a superscript 2 (²)? The way I get it is by copying it from previous posts. Can you please tell me how to type it?
2006-10-16 17:14:31 · answer #4 · answered by عبد الله (ドラゴン) 5 · 0⤊ 0⤋
2*2*2*2*2*2*2*2, 256
2006-10-16 17:12:55 · answer #5 · answered by james t 2 · 1⤊ 0⤋