How fast must the ping-pong ball move m/s ?

1 ⤊

A 7.0 kg bowling ball moves at 2.35 m/s. How fast must a 2.20 g Ping-Pong ball move so that the two balls have the same kinetic energy?

2006-10-16 07:51:49 · 4 answers · asked by activegirl 1 in Science & Mathematics ➔ Physics

KE = (1/2)m*v^2 = (1/2)*(7 kg)*(2.35^2) = 19.32 J

Vp = Sqrt[2*KE/m] = Sqrt[2*19.32 J/ .0022 kg] = 132.528 m/s

2006-10-16 08:07:58 · answer #1 · answered by resurrection_of_t_o 2 · 1⤊ 0⤋

1/2 Mbb v^2 = 1/2 Mppb v^2

Mbb/Mppb = vppb^2/vbb^2

Mbb/Mppb * vbb^2 = vppb^2

Sqrt (Mbb/Mppb * vbb^2) = vppb

2006-10-16 08:05:35 · answer #2 · answered by Holden 5 · 0⤊ 0⤋

.5*7*(2.35)^2=.5*.0022*V^2
V=132m/s

2006-10-16 08:02:42 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋

I only play foot ball........

2016-05-22 06:51:31 · answer #4 · answered by ? 4 · 0⤊ 0⤋