yes
2006-10-16 06:16:42
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answer #1
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answered by R 3
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Yes.
5-5=0
5=5
2006-10-16 06:23:29
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answer #2
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answered by quilter24 2
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yes 5-5=0
2006-10-16 06:22:56
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answer #3
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answered by Anonymous
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It is one of the axioms of the real numbers that every real number (denoted by a to represent any real number) has an additive inverse, that is, there exists a unique real number, denote it by b, such that a+b=0. In usual arithmetic, if you have any particular real number a, then its additive inverse is usually represented by -a. Thus, the additive inverse of 5 is -5. Hence, by the axiom, 5+(-5)=0. In fact, when doing arithmetic, we are normally lazy and just write 5-5=0 instead of 5+(-5)=0.
I hope that this helps!
2006-10-16 11:32:23
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answer #4
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answered by friendly_220_284 2
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5-5=0 Is Correct Because a number minus its self is always 0.
2006-10-16 06:59:06
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answer #5
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answered by coolcat87@ameritech.net 2
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Actually a rigorous proof has never been done for 5-5=0. If you read Principia Mathematica it proves 1+1=2.
5-5=0 is normally taken for granted.
2006-10-16 06:34:15
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answer #6
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answered by Anonymous
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Yep!
Just like:
4 - 4 = 0
3 - 3 = 0
2 - 2 = 0
1 - 1 = 0
0 - 0 = 0
2006-10-16 06:22:41
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answer #7
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answered by x_Super_Social_Superstar_x 3
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yes it does= 0
2006-10-16 06:17:01
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answer #8
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answered by derek6711 3
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Assuming you're working in a base higher than five (otherwise the digit 5 would not be used) then you are correct regardless of which base you are working in.
As has already been mentioned this is just a demonstration of the inverse and the integers form a ring so the inverses exist.
2006-10-16 12:07:23
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answer #9
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answered by tringyokel 6
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5-5=10
lol
2006-10-16 06:21:35
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answer #10
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answered by Anonymous
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OK if your having problems lets do it the 5 year old way
take 5 apples (thats the same number of fingers and thumbs on one hand and place them on the table
now take away 5 apples and give them to mummy
how many apples do you have left on the table?
my guess would be none
2006-10-16 06:38:11
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answer #11
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answered by Anonymous
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