2006-10-16 05:27:00 · 16 answers · asked by Rob 1 in Science & Mathematics ➔ Astronomy & Space
it is always moving as a result of what is happening on its surface. However the little things on top of the big earth are so insignificant that the motion is not even worth trying to detect. Even if everyone moved in the same direction at the same time they are a trivial percentage of the earth's mass so they count for almost nothing.
2006-10-16 05:30:49 · answer #1 · answered by Rich Z 7 · 0⤊ 0⤋
No. In order to move the earth, you would need to apply a net force to it. This could not happen for 3 reasons:
1) You need to apply a great enough force to escape Earth's gravitational pull (the escape velocity). Otherwise, the push you give the earth on take-off would equal the pull of gravity coming back.
2) Even if you did this, the population is distributed evenly around the earth, so that much of the force would cancel.
3) If you addressed 1) and 2), the mass of people leaving would be at most 6*10^9*100 kg = 6*10^11 kg. Since the earth is about 10^13 times as massive as this, it would have very little impact.
2006-10-16 12:46:19 · answer #2 · answered by stormfront105 2 · 1⤊ 0⤋
Greetings!
Indeed it would move. Many things the people on this planet do effect what the earth does. Basic physics, like for every action there is an opposite and equal reaction.
As an aside and risking exposing the government which has launched a plot against fat people let me say this. Their scientists have convinced them that because there are so many fat people in America, it has caused the Earth to be weighted down, and as a result is now closer to the Sun.
This they claim is the true culprit behind Global Warming.
To avoid a full blown political issue, the government is trying to wage a friendly campaign to get people to lose weight.
Good Luck
2006-10-16 12:37:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Let us take the population of Earth to be 6 billion.There are children old and young people. Assume an average mass of 60kg. Let us assume that for the worst case the weight of all the 6 billion people is applied as a concentrated load on Earth. Total force=6*10^9*60*9.81 Newtons
Take factor of 3 to simulate the dynamic loading
=3*6*10^9*9.81N=176.58*10^9
Mass of Earth=6*10^24kg
Possible acceleration on earth due to this force
=force/mass=176.58*10^9Newtons/6*10^24kg
=29.43*10^-15m/sec^2
=.02943*10^-12m/sec^2
=.02943pico m/sec^2
which is very very low and
as good as non existent.
Hence no movement
2006-10-16 14:09:35 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
Assuming they are distributed evenly across the globe, no; the force of people jumping at point X would be cancelled out by the people on the other side of the Earth.
If they are not evenly distributed, the Earth would move, but not any measureable amount.
2006-10-16 12:31:04 · answer #5 · answered by poorcocoboiboi 6 · 0⤊ 0⤋
No, the moon moves millons of tons of water each day and the earth does not move.
2006-10-16 12:29:31 · answer #6 · answered by salter 2 · 0⤊ 0⤋
no it wouldn't because the force of the shock from hitting the ground would equal out so basically it would just force the earth inward if anything at all
2006-10-16 13:12:38 · answer #7 · answered by Scotty Envy 2 · 0⤊ 0⤋
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Look at this site. Sounds like someone wants to try it out!
2006-10-16 12:37:00 · answer #8 · answered by jooker 4 · 0⤊ 0⤋
Absolutely not. Not in the grand scheme of things
2006-10-18 22:28:42 · answer #9 · answered by onabluehighway 1 · 0⤊ 0⤋
Contrary to the song, nope.
2006-10-16 12:29:20 · answer #10 · answered by kekeke 5 · 0⤊ 0⤋