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A fisherman yanks a fish out of the water with an acceleration of 4.5m/s.s using very light fishing line that has a 'test' value of 22N. The fisherman unfortunately loses the fish as the line snaps. What can you say about the mass of the fish?

2006-10-16 05:23:29 · 5 answers · asked by Anonymous in Science & Mathematics Physics

guys...... answer is
mass of fish should be less than 1.5 kg

2006-10-16 05:53:04 · update #1

5 answers

Since the fish is accelerated at 4.5 m/s^2, the sum of the forces is equal to this acceleration times the fish's mass. In order not to break the line, the fish's mass should be less than the amount that would produce the breaking tension. So find that mass:
M*4.5 = 22-M*9.8
solve for M, I get M = 1.5 kg.
Thus we can say that the mass of the fish was greater than 1.5 kg.

2006-10-16 07:15:07 · answer #1 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0 0

test value of fishing line=22N
acceleration applied=4.5 m/sec^2
Max value of permissible mass of fish
=22N/4.5m/sec^2=4.88kg
Since the line has snapped
the mass of the fish>4.88kg

2006-10-16 12:43:57 · answer #2 · answered by openpsychy 6 · 0 1

Well. Force = Mass X Acceleration. So, Mass = Force / Acceleration.
Mass = 22 / 4.5 = 4.88Kg.

2006-10-16 12:28:39 · answer #3 · answered by linkin_park_rocks_my_socks007 2 · 0 1

net force= mass x acc
net force is the sum of the forces on the fish: -weight+tension
so :-weight+tension=ma
since it broke the tension was at its max
tension(max)=ma+weight
so: mg+ma=tension(max)
m=tension(max)/(g+a)

the mass is about 22N/14.3= 1.54 kg

2006-10-16 12:49:00 · answer #4 · answered by socrmom 2 · 1 0

why do you ask the question if you give us the answer later?

is that not the point of Yahoo! Answers?

2006-10-16 20:11:00 · answer #5 · answered by mcdonaldcj 6 · 0 0

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