would the friction experienced by the car and the road increase? if so, how can this be calculated?
2006-10-16 04:54:58 · 13 answers · asked by ann 2 in Science & Mathematics ➔ Physics
but since surface area does not affect friction, would the friction experienced by the car and the road increase? if so, how can this be calculated?
2006-10-16 05:05:14 · update #1
"In the case where a surface is soft, there is molecular adhesion, and in rolling and fluid friction, the coefficient of friction is not a simple number. The coefficient may be dependent on the area of the surfaces, the amount of deformation, the amount of adhesion, the shape of the surfaces, the radius of the wheel or the viscosity of the fluid." [See source.]
A soft "tyre" on hard surface changes the make up of the coefficient of friction in F = kN; where F is the friction force, k is the complex coefficient of friction, and N is the normal weight perpendicular to the surface. Area is just one of several factors that can affect the value of k for soft materials.
k is generally found empirically (by experiments) because so many factors do affect its value. There are some equations for fluid coefficients using Reynolds numbers, but I don't think you want to go there. Besides your tyre is not a fluid.
PS:
For hard surface on hard surface, F = kN does not depend on the area of the contact. That is, k does not change with the area; so, for example, a meter square tile sliding along a hardwood floor would have the same k as a centimeter square tile over the same floor. Check this out:
"An interesting result of this equation is that in the case of sliding friction of hard surfaces, the friction is independent of the area of the surfaces. In other words, it is just as difficult to move a 1 square-cm object as a 1 square-meter object, if they both are pressed to the surface with the same amount of force." [See source.]
2006-10-16 05:48:18 · answer #1 · answered by oldprof 7 · 2⤊ 0⤋
When a tire isn't properly inflated, it deforms near the bottom where it contacts the road. As it rotates, this results in a constant compressing and expanding of the tire, and generates frictional heating in the rubber. This causes the car to lose Kinetic Energy at greater rate and requires more work/force from the engine to compensate.
Hence, properly inflate the tire, bring it up to constant speed and take your foot off the gas pedal. Time how long it takes for the car to drop to a certain speed. Deflate the tire(s) a little and repeat the same procedure. Its speed should drop faster.
2006-10-16 05:24:03 · answer #2 · answered by entropy 3 · 1⤊ 0⤋
When the tire is deflated there is a greater surface area coming into contact with the ground. This causes increased friction. On a straight away it can significanly reduce your ability to accelerate as well as increase gasoline consumption.
2006-10-16 05:01:20 · answer #3 · answered by imacdaddy01 2 · 0⤊ 0⤋
Dude. the area of contact between the tyre and the road has increased thats why the friction increases, which makes it encounter more resistance...
2006-10-16 05:34:11 · answer #4 · answered by linkin_park_rocks_my_socks007 2 · 0⤊ 1⤋
Of course there would be more friction, more rubber is in contact with the ground.
In order to calculate this you need the formula:
3x divided by 5/6 of the resistance quotem when x = the area of rubber in contact (cm squared)
2006-10-16 04:59:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋
more rubber will be in contact with the road so more friction. If you drive for a bit however things will improve as running on the rim will reduce friction.
2006-10-16 04:58:22 · answer #6 · answered by deflagrated 4 · 0⤊ 0⤋
this might sound unusual in spite of the undeniable fact that it may truly be the wheels themselves, dependant on what make of automobile that's and no count if the wheels are unique. I used to have an Impreza and since the tires saved loosing rigidity i complained to Subaru. It became out that there have been a project with the producing of the wheels and in a roundabout way they had substitute into porous so the air interior the tyres replaced into basically seeping by using them!! various Imprezas the place recalled interior the tip to have the wheels replaced freed from fee via Subaru!!
2016-12-26 20:35:46 · answer #7 · answered by Anonymous · 0⤊ 0⤋
when the tire is flat is creates a larger patch area. This larger patch area comes in contact with the ground creating more friction. More friction = more resistance.
2006-10-16 05:03:22 · answer #8 · answered by kimchee_boi 3 · 0⤊ 0⤋
The air pressure inside the tyre ensures that the surface area maintains a strict inertial motion due to equal pressure on the inside and outside simultaniously.
2006-10-16 05:04:32 · answer #9 · answered by moebiusfox 4 · 0⤊ 0⤋
Because of the weight being borne by the tire. If you have ever ridden a bicycle with flat tires, you'd know exactly what I mean. The properly inflated tire has less contact with the road, less resistance, and wears better also.
2006-10-16 04:57:27 · answer #10 · answered by HelpfulHanna 3 · 0⤊ 0⤋