2006-10-16 04:45:30 · 5 answers · asked by 9929 3 in Science & Mathematics ➔ Biology
use a punnet square
X = dominant allele for tall
y = recessive allele for short
Xy * Xy = XX, Xy, Xy, yy
phenotypic ratio is 3:1 Tall:Short
2006-10-16 04:57:51 · answer #1 · answered by Anonymous · 1⤊ 0⤋
For any heterozygous individual the Gene and its allele are not the same
T=tall assuming this is dominat
t=short
hence: Tt X Tt
gametes = T t x T t
F1 gen: TT Tt Tt tt
thus 75% are tall and 25% short
Tt are hetrozygous Tall but carry gene for shortness
TT are homozygous tall
tt are homozygous short
2006-10-16 05:09:38 · answer #2 · answered by quinton p 2 · 0⤊ 0⤋
The phenotypic expression will be 2:2 ( Two Tall and Two short) assuming that the height is governed by the dominant allele. However, among the two tall plants ,one will be homozygous (TT) and one will be heterozygous. The genotypes will be TT, Tt, tt, tt.
2006-10-16 06:13:50 · answer #3 · answered by prakash s 3 · 0⤊ 1⤋
Tt x Tt
T t T t
TT Tt Tt tt
3:1
all the ones with T that is dominant allele will be tall
only tt which is homozygous recessive will be small
2006-10-16 06:28:51 · answer #4 · answered by wazirsaira 1 · 0⤊ 0⤋
Theoretically, A. All you needed to do to get the answer to the question was create a punnett square. Aa x Aa = 25% AA, 50% Aa, 25% aa
2016-05-22 06:25:11 · answer #5 · answered by Anonymous · 0⤊ 0⤋