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this in fraction form like this... ___5____ is over the x -6(x negative 6) = 7 and I need to find value of x

2006-10-16 04:23:10 · 12 answers · asked by Suzicat 1 in Science & Mathematics Mathematics

12 answers

5=7x-42
7x=47
x=47/5

2006-10-16 04:25:15 · answer #1 · answered by raj 7 · 0 1

5= 7(x-6); 5=7x-42; 42+5=7x; x=47/7; x= 6 5/7

2006-10-16 06:27:26 · answer #2 · answered by Anonymous · 0 0

hey u can apply simle cross multiplications as follows:
your question is:
5 = 7_
X-6 1

5 = 7_
X-6 1

This results in :
5*1 = 7*(X-6)
5 = 7X -42
7X = 42+5
7X = 47
X = 47/7

2006-10-16 04:33:05 · answer #3 · answered by abcd_123 2 · 0 0

5/(x-6)=7 multiply both sides by x-6
5=7(x-6)=7x-42 add 42 to each side
47=7x divide by 7
x=47/7

2006-10-16 04:36:47 · answer #4 · answered by yupchagee 7 · 0 0

5/x-6=7
5/x=7+6
5/x=13
x=5/13

2006-10-16 05:31:17 · answer #5 · answered by Sean 3 · 0 0

multiply both sides by x
5(x/x) - 6x = 7x
subtract 6x from both sides to get axx x's on one side
5 = 7x + 6x, (x/x = 1)
factor:
5 = x(7+6)
divide both sides by 13 (=7+6) and swap sides for convention:
x = 5/13

2006-10-16 04:32:36 · answer #6 · answered by Helmut 7 · 0 0

5/x-6=7
5/x=7+6
5/x=13
5/x over 1/x=13 over 1/x
5/x(x/1)=13(x/1)
5=13x
5/13=x
my answer is 5/13

2006-10-16 05:29:34 · answer #7 · answered by mich 2 · 0 0

as i understand this question, 5/(x-6)=7,
then 5=7(x-6)
5=7x-42
5+42=7x
7x=47
x=47/7
x=6.72

2006-10-16 04:29:52 · answer #8 · answered by Genius 2 · 0 0

5/[x-6]=7
7[x-6]=5
7x=5+42
x=47/7
=6+5/7
=6.71

2006-10-16 04:52:57 · answer #9 · answered by openpsychy 6 · 0 0

if it is 5 : ( x - 6 )= 7 then------- x= +7

if it is (5 : x) - 6 = 7 then--------- x= +5/13

that's right!

2006-10-16 04:37:45 · answer #10 · answered by Lulu 1 · 0 0

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