A passenger train can travel 325 mi in the same time a freight train take to travel 200 mi. If the speed of the passenger train is 25 mi/h faster than the speed of the frieght train, find the speed of each.
2006-10-16 01:44:22 · 6 answers · asked by Cindy g 1 in Education & Reference ➔ Homework Help
Freight = 40 mi/hr, Passenger = 65 mi/hr
Let x = Freight speed. The equation then is
325/(x+25) = 200/x
Passenger time to travel 325 = Freight time to travel 200
Cross multiply to get:
325x = 200(x+25)
Expand:
325x = 200x + 5000
Move x's together
125x = 5000
Divide
x = 5000/125 = 40
Passenger speed = x + 25 = 65
2006-10-16 02:31:33 · answer #1 · answered by Dentata 5 · 0⤊ 0⤋
The answer is the cargo train is traveling 40 miles per hour, and the passenger train at 65 miles per hour. Now try to put that into and equation to support this answer. Sometimes it helps to work backwards to figure out a problem. Good luck
2006-10-16 09:02:41 · answer #2 · answered by stretch 7 · 0⤊ 0⤋
First off that is a math problem not a word problem. You need to study. Do some preactice problems in your Math text book. We could give you the answer but that would not help you leran to solve the problems. Get with a study pal, spend time after school getting help with the teacher, ask your parents or a family member to sit down and show you step by step how to do it and then practice, practice & practice.
2006-10-16 08:49:23 · answer #3 · answered by Shayna 6 · 0⤊ 1⤋
That isn't a word problem, it's a mathematical problem.
2006-10-16 08:47:14 · answer #4 · answered by Anonymous · 0⤊ 0⤋
that's bloody impossible
2006-10-16 09:06:23 · answer #5 · answered by Bex 1 · 0⤊ 0⤋
And the word is????
2006-10-16 08:46:44 · answer #6 · answered by Hamish 7 · 0⤊ 1⤋