java random output from a spacific range and in increasing order?

Question

hi everyone her I have a problem for you and actully my problem and I wanna share it with everyone here oky

The problem haw to generate a list of integers from x to y e.g. 1-100 and it is generated in an increasing order e.g. 1,6,23,25,29,34,........ 98 and actually this is the real problem
the needed number of integers is 20

The Q is how to do that by coding and is there a method in java that handel this issu ?
================
oky have a look what i done so far
java code:
mport java.util.*;


public class mainclass{
public static void main(String [] args ){
Random rand = new Random();
int x =1;
int curr =0;
for(int t =0;t<10;t++){



while(x100){
x = rand.nextInt() % 100;

}
curr =x ;
System.out.println(x) ;

}



}}

any idea :)

they must be generated in order without sorting them at the end

Answer 1

I don't really know how to help you then, sorry. It seems like it would almost be impossible to get 20 integers in a row, because at some point you are bound to get a high number and limit your possible future numbers significantly.

what you are doing looks good, but i do have one code suggestion. When you are getting your rand int, you could call nextInt(101). See api link below for why its 101.

I don't know if this is acceptable, but you could limit the range for each number. For instance, the first has to be from 1 - 5, the second from 6 - 10, and so on.

Answer 2

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