2006-10-15 18:14:10 · 7 answers · asked by RydrCup99 1 in Science & Mathematics ➔ Mathematics
-5(3a+2b)-2(4a-b) =
(-5)(3a)+(-5)(2b)+(-2)(4a)+(-2)(-b) =
-15a-10b-8a+2b =
(-15-8)a+(-10+2)b =
-23a-8b
2006-10-15 18:15:26 · answer #1 · answered by Jesse 2 · 1⤊ 0⤋
You have to multiply -5 to both numbers in the parenthesis and then do the same with the -2.
-5(3a)+(-5)(2b)-2(4a)-(-2)(b)
-15a-10b-8a+2b add like terms
-23a-8b
2006-10-16 11:03:50 · answer #2 · answered by scheerbarbara 1 · 0⤊ 0⤋
-5(3a+2b)-2(4a-b)
= -15a-10b-8a+2b
= -23a-8b
2006-10-16 01:22:56 · answer #3 · answered by Andrily 1 · 1⤊ 0⤋
-5(3a+2b)-2(4a-b) =
-15a - 10b - 6a + 2b =
-21a - 8b
2006-10-16 01:19:09 · answer #4 · answered by Helmut 7 · 0⤊ 1⤋
-15a - 10b - 8a +2b
= -23a - 8b
2006-10-16 01:23:24 · answer #5 · answered by Anonymous · 0⤊ 0⤋
-5(3a+2b)-2(4a-b)
=-5*3a-5*2b-2*4a-2*(-b)
=-15a-10b-8a+2b
=-(15a+10b+8a)+2b
=-(23a+10b)+2b
=-23a-10b+2b
=-23a-8b
=-(23a+8b)
2006-10-16 01:27:02 · answer #6 · answered by Anonymous · 0⤊ 0⤋
-23a-8b
2006-10-16 01:18:31 · answer #7 · answered by Anonymous · 1⤊ 0⤋