1 Amp = 1 Coulomb/sec = 6.241×10^18 electrons /sec
Assuming the entire beam hits the screen,
340 μA(1 A/10^6 μA)(6.241*10^18 electrons/ 1 Amp-sec) = 2.12194*10^15 electrons/sec
2006-10-15 18:16:47
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answer #1
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answered by Helmut 7
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Amperes is the unit of electric current. Amperes = coulombs/second.
Thus, you want to divide 0.000340 A (340 µA) by the charge of a single electron, which is 1.60217646 × 10^-19 coulombs (which is the same as multiplying 340 µA by the number of electrons per coulomb).
The result:
2122113315782956.8910280956193...
And since you can't have a fraction of an electron, I suppose you'd just round down. Thus, it's
2,122,113,315,782,956 electrons per second.
this is the best answer
2006-10-16 00:37:26
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answer #2
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answered by Ekant 2
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Amperes is the unit of electric current. Amperes = coulombs/second.
Thus, you want to divide 0.000340 A (340 µA) by the charge of a single electron, which is 1.60217646 × 10^-19 coulombs (which is the same as multiplying 340 µA by the number of electrons per coulomb).
The result:
2122113315782956.8910280956193802
And since you can't have a fraction of an electron, I suppose you'd just round down. Thus, it's
2,122,113,315,782,956 electrons per second.
2006-10-15 18:14:52
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answer #3
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answered by extton 5
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those answers are correct. the only thing i can think of is that it's a trick question. not all of the electrons hit the screen. some hit the appature mask in front of the screen and some miss the screen due to overscan.
2006-10-15 19:15:18
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answer #4
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answered by Anonymous
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How do you know no one was right? You need to do this yourself! Your set of questions shows you should instead be doing your own homework.
2006-10-15 19:07:54
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answer #5
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answered by Frank N 7
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what makes you think this time will be different?
how do you know they were wrong last time?
2006-10-15 18:11:36
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answer #6
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answered by alledgedflatlander 3
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