here is the problem........ I am stumped
write an equation of a line that has a y-intercept of 3 and is parallel to the line whose equation is given.
y=-6x+2
yeah...... I don't understand any of it
2006-10-15 17:36:04 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Geography
The slope-intercept formula of a line is y = mx + b, where m = slope of the line and b is the y intercept.
To be parallel to y = 6x + 2, the slope of your line has to be -6 (the coefficient of x)
The y intercept is the value of y when = 0. (In the above equation it is 2), so
y = -6x + 3
2006-10-15 17:47:23 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
The equation of a line is y=mx +b , where m is the slope and b is the y intercept.
For a line parallel to y=(-6x) +2, the slope is the same---(-6).All that is different is the y intercept which is 3 rather than 2.
So the equation is:
y=(-6)x+3
2006-10-16 02:02:29 · answer #2 · answered by True Blue 6 · 0⤊ 0⤋
Given that the Line s are Parllel their slopes will be equal.Given the Y intercept......
The equation will look like y = -6x+y-intercept
Therefore the eqution of required line is y = -6x+3
2006-10-15 17:48:14 · answer #3 · answered by Kish 2 · 0⤊ 0⤋
y=-6x+3
the 6x is equal to the slope and if x=0 than y=3 so the y int. is 3
2006-10-15 17:41:31 · answer #4 · answered by bolla 3 · 1⤊ 0⤋
y=-6x+3
2006-10-15 23:07:36 · answer #5 · answered by Habesha 1 · 0⤊ 0⤋
easy
y = ax + b; a is the slope b is the y intercept
thus for you :
y = -6x + 3
2006-10-15 20:57:00 · answer #6 · answered by gjmb1960 7 · 0⤊ 0⤋
I love how you think this can relate to Geography.
2006-10-15 17:39:54 · answer #7 · answered by nalaredneb 7 · 1⤊ 0⤋
Isn't this a MATH question
2006-10-16 14:43:37 · answer #8 · answered by Chris 3 · 0⤊ 0⤋