it lands 1.65m from the foot of the tabletop.
please explain steps. thank you.
2006-10-15 16:22:29 · 6 answers · asked by j a 1 in Science & Mathematics ➔ Physics
As there is no force in the horizontal direction, horizontal velocity does not change.Time taken = distance divided by speed =.67s
2006-10-15 20:57:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
During free-fall, the horizontal component of the motion does not change; since the marble lands 1.65 meters from the table, it took 1.65/2.45=.67 seconds to fall from the table to the floor.
2006-10-15 16:33:27 · answer #2 · answered by bruinfan 7 · 0⤊ 0⤋
This is simple projectile motion from a horizontal launch:
The Range (R) is 1.65 m
The horizontal velocity (vx) is 2.45 m/s
You are looking for the drop time (t)
R = vx*t
t = R/vx
t=1.65 m / 2.45 m/s
t = 0.67 s
2006-10-15 16:37:26 · answer #3 · answered by TM 3 · 0⤊ 0⤋
speed, s=2.45 sec, time, t=? gravity, g=-9.8 meters per second. distance, d = 1.65 mete
TIME is equal to speed divided by distance. in this case t=s/d, 2.45 m/s divided by 1.65 = 1.48 seconds gravity although i dont remember i took physicis a long time ago
2006-10-15 16:29:09 · answer #4 · answered by eric_j_hess 2 · 0⤊ 0⤋
Q. Did the marble bounce or perhaps roll, when it hit the floor? It should do in most cases.
2006-10-15 16:27:16 · answer #5 · answered by dryheatdave 6 · 0⤊ 0⤋
is there enough info?
2006-10-15 16:31:16 · answer #6 · answered by Anonymous · 0⤊ 0⤋