Differentiate: y =csc^2x + cos^2x?

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2006-10-15 15:46:29 · 3 answers · asked by j a 1 in Science & Mathematics ➔ Mathematics

y = csc² 2x + cos² 2x
y' = -4 (cos2x.sin2x + csc²2x.cot2x)

2006-10-15 16:02:18 · answer #1 · answered by M. Abuhelwa 5 · 0⤊ 0⤋

y'= 2cscx(-cscxcotx) + 2cosx(-sinx)
y'= -2(1/sinx)(1/sinx)(1/sinx)(cosx) -2sinxcosx
y'= -2((csc^2x)cotx + sinxcosx)

2006-10-15 22:50:56 · answer #2 · answered by Greg G 5 · 0⤊ 0⤋

dy/dx= -2cosec2xcot2x-2sin2x

2006-10-15 22:52:03 · answer #3 · answered by khotl73 2 · 0⤊ 0⤋