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how much work is done by a person who picks up a 3-kg crate from the floor, raises it 2 m, and sends it flying with a speed of 4 m/s? and how?

2006-10-15 15:26:18 · 2 answers · asked by rocky s 1 in Science & Mathematics Physics

2 answers

In the lifting part: 3kg*9.8m/sec^2*2M=6 joules
In the throwing portion: Work = .5*m*v^2=.5*16*3=24 joules
Therefore, a total of 30 joules worth of work is done for these combined acts.

2006-10-15 16:39:35 · answer #1 · answered by bruinfan 7 · 0 0

The work done lifting it is f*d = w*d = m*g*d. (Hint: a Newton-meter is a joule.)
Giving it speed of V gives it kinetic energy = (1/2)*m*v^2. (This will also be joules)

2006-10-15 22:34:53 · answer #2 · answered by sojsail 7 · 0 0

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