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(-5)by the power of 3= +625
-5 by the power of 3= -625

6*-2 by the power of 3 -2 *-6= -36

2006-10-15 15:05:05 · 7 answers · asked by Anonymous in Education & Reference Homework Help

7 answers

-5 to the third power is -125. I don't even know what you are trying to ask for the second problem.

2006-10-15 15:13:18 · answer #1 · answered by Nelson_DeVon 7 · 0 0

Both (-5)^3 and -5^3 are -125. That's true for all odd exponents. However, if you were taking an EVEN exponent, they'd be different. For example, (-5)^4 = 625, but -5^4 = -625.

6*-2^3 = 6*-8 = -48.

All these problems rely on the order of operations that says you first do anything in parentheses. Next you do exponents. Then (after the exponents are done), you multiply and divide, and finally you add and subtract.

2006-10-15 22:13:01 · answer #2 · answered by dmb 5 · 0 0

(-5)^3 = - 625
negative 5 to the third power is negative 625; a negative times a negative is positive, a positive times a negative is negative.

-5^3 = - 625, - (5 x 5x 5)

2006-10-15 22:09:09 · answer #3 · answered by LaCosaMasBella 3 · 0 0

no the first one should be +125
the second one should be -125
the third one should be -12 to the power of 15
(oder of operations for number three- multiply -2*-6 first to get +12 then add +12and+3 since you got tid of the - when you multiplied a - by a -)
hope this helped

2006-10-15 22:14:11 · answer #4 · answered by luvkitties 4 · 0 0

(-5)^3 should be -125 because (-5)^3 = (-5)(-5)(-5) = (25)(-5) = -125.

-5^3 should also be -125 because that's -(5)^3 which = -(5)(5)(5) = -(25)(5) = -125

I don't really understand what you're saying with that last line though, sorry!

2006-10-15 22:11:51 · answer #5 · answered by mizzdorkyangel 2 · 0 0

(-5)^3 = (-5)(-5)(-5) = -125
-5^3 = -1 * 5^3 = -125

6* -2^3 = 6* -8 = -48

2006-10-15 22:11:03 · answer #6 · answered by PatsyBee 4 · 0 0

(-5)³ is -125

-(5³) is -125

I am perhaps confused by your notation on the last problem: If I interpret it correctly:

(-2)³ = -8
6 x (-2)³ is -48

2006-10-15 22:16:02 · answer #7 · answered by Computer Guy 7 · 0 0

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