The square root of a number (B) is a number (A), if and only if A times A equals B.
1. +/- (1/9)
2. +/- (.5)
3. +/- (10/3)
4. +/- (.01)
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Rational numbers are numbers that can be written as a fraction (a ratio). So any number that ends or is a repeating decimal is rational.
1) 8.3 can be written as 83/10. Rational.
2) Square root of 10 is irrational, it isn't a repeating or ending decimal.
3) 22/7 is a fraction. Rational.
4) 3.625 can be written as 29/8. Rational.
5) 50 is an ending number. Can be written as 50/1 or 100/2. Rational.
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Looking things up is good for you. Try it some time.
2006-10-15 14:50:07
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answer #1
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answered by mizzdorkyangel 2
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For 1 and 3, just find the square roots of the numerator and denominator. For 2 and 4 change them to fractions and do the same thing. #3 is 25/100, so the square root is 5/10 = 1/2 = .5.
Rational numbers have terminating or repeating decimals, or are written as fractions with integers for both numbers. So 1,3 4 and 5 are rational.
For your last question, there is a procedure for it, but these days most people do an estimation process. You know the square root of 21 is between 5 and 6. So through trial and error try to make it a little more exact by choosing decimals and seeing how close you can get.
2006-10-15 14:53:38
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answer #2
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answered by PatsyBee 4
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I can do simple square roots, like 1-4, in my head, but more difficult ones need a calculator.
All square roots are + or -
1) 1/9
2) 5
3) 10/3
4) .01
A rational number is by definition a number that can be expressed as a fraction a/b, where a nd b are integers, and b not equal 0. All finite and repeating decimal numbers can be expressed as such.
1) yes
2) no
3) yes
4) yes
5) yes
2006-10-15 14:57:05
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answer #3
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answered by Computer Guy 7
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the square root of a number is a number that is multiplied by itself to get a number ex. 3 x 3 = 9 thus the square root of 9 is 3.
1. 1/9
2. .5
3. 10/3
4. .01
ratinoal numbers have a definate end... irrational numbers do not
1. rational
2. irrational
3. irrational i think
4. rational
5. rational
2006-10-15 14:52:50
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answer #4
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answered by Victoria O 2
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Sorry, yet you have stated the problem incorrectly and it won't be able to be solved as stated. the way it reads good now could be: 80 instances the squareroot of two + 20 the squareroot of ? Please examine problem lower back and then submit a correct version of the problem.
2016-12-16 08:19:35
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answer #5
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answered by mcgeehee 4
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thats too much .. if u wanna help ask only for one not them all at once!
thats too lazy of you ,, depend on yourself honey!
2006-10-15 14:45:24
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answer #6
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answered by Alex 2
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are you in kindergaten
2006-10-15 14:50:55
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answer #7
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answered by Anonymous
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