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im more of a visual learner so heres a conversion:
7.04 grams of C5H5N
ive coverted it to moles, which is 0.09 i think
so i guess just converting moles to molecules is my question.

2006-10-15 14:12:05 · 6 answers · asked by lo 2 in Science & Mathematics Chemistry

yepp im sure.

2006-10-15 14:17:06 · update #1

6 answers

It is the same as dozen. If you have 2.5 dozen of "atoms" you will do
2.5 x 12 to find out the number of "atoms"

Well 1 mol of anything is the avogadro number 6.02x10^23. so if you have 2 moles of something you have:

2 * 6.02 x10^23 of those things.

OK?

Now, how about throwing 0.00001 moles of dollars my way?
It's small, man.
Can't you spare that?

2006-10-15 15:29:13 · answer #1 · answered by Dr. J. 6 · 0 0

a million. The molar mass of this substance, in grams/mole is got here upon via looking up the atomic weight of C, H and O. the fee is 12.01*9 + a million.01*8 + sixteen.00*4 = one hundred eighty.sixteen g/mol. There are 6.022e23 molecules in a mole, so the aspirin's mass is (2.52e23 molecules) * (one hundred eighty.sixteen g/mole) / (6.022e23 molecules/mole) = seventy 5.39 g 2. each glucose molecule demands 6 carbon atoms, so we've a million.260e21 / 6 = 2.1e20 molecules. it fairly is (2.1e20 molecules / 6.022e23 molecules/mol) = 3.487e-4 mol. The molar mass of glucose additionally works out to be one hundred eighty.sixteen g/mol, so the mass is (3.487e-4 mol * one hundred eighty.sixteen g/mol) = 0.06282 g

2016-12-13 08:59:19 · answer #2 · answered by ? 4 · 0 0

Safely & Permanently Remove Moles, Warts and Skin Blemishes

2016-05-16 11:13:43 · answer #3 · answered by Kimberly 4 · 0 0

multiply moles by avogadro's number 6.022 x 10^23..he's got the number wrong

2006-10-15 14:23:32 · answer #4 · answered by The Cheminator 5 · 1 0

uhmm wait let me think because i am taking college chemistry and i don't remember converting mole to molecule. it could be multiplying .009 by 6.02X10^23
WHAT DO U THINK
HEY I AM RIGHT YOU MULTIPLIED IT BY THAT NUMBER GO TO THIS WEBSITE IT TELL U
http://www.wwnorton.com/chemistry/concepts/chapter4/ch4_2.htm
Tell me if u have any question about my answe

2006-10-15 14:15:42 · answer #5 · answered by Jason 4 · 1 2

0.09*6.023*10^23

2006-10-15 22:25:03 · answer #6 · answered by Rajchem 2 · 0 0

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