i am in Algebra 1 and im trying to solve a math equation (7/8)x-(1/4) (3/4)x=(1/16) x the parenthesie are supp

Question

i am in Algebra 1 and im trying to solve a math equation (7/8)x-(1/4) (3/4)x=(1/16) x the parenthesie are suppost to be fractions i have to solve these by clearing the fraction and i keep comming up with the wrong #s

Answer 1

(7/8)x-(3/16)x=(1/16)x
[14-3/16]x=1/16 x
(11/16)x=1/16x
possible only if x=0

Answer 2

Not sure what you mean by cross multiply, but all you have to do is isolate x using the allowed rules of alegbra (I guess that's just restating the question): 30 = 8x (x-1) 30 = 8x^2 - 8x [distribution of 8x into (x-1)] 8x^2 - 8x - 30 = 0 [subtract 30 from both sides] Now you can use the quadratic formula: a is 8, b is -8, and c is -30. The quadratic formula is: x = (-b +- sqrt(b^2 - 4*a*c))/(2a) Note the +-: you'll generally get two different answers because you do the equation twice, once with a plus, once with a minus. Also note that the notation x^2, for instance, means "x-squared", in case you've never seen that.

Answer 3

First multiply out the fraction (1/4)(3/4)x to (3/8)x. Then multiply all terms by 16 to clear the fractions. You should get 14x - 6x = x which simplifies to 7x = 0. Are you sure you have written the equation right? Every term contains x. Maybe another bracket is left out.

Answer 4

I'd group all the x-values on the left side of the equals sign, and assign the value zero to the equation (on the right side of the equals sign):

7/8x - (1/4 * 3/4x) - 1/16x = 0
7/8x - 3/16x - 1/16x = 0
14/16x - 3/16x - 1/16x = 0
14/16x - 4/16x = 0
10/16x = 0
5/8x = 0
therefore, x = 0

otherwise, as you've written the problem, it does not yield a legal answer. I hope this helps. Best of luck to you!

Answer 5

if you convert the fractions to 32nds then x should equal 1 where the total answer should be 8/32

Answer 6

This is a good Algebra site:

Answer 7

can u write it again...it looks confusing to solve..