If you must use 15 or fewer coins, how many different combinations of coins can be used to make $1.00?

Answer 1

The previous answerer forgot about the "or fewer" part. Thus you could also have -

4 quarters (4 is less than 15)
2 half dollars
10 dimes
2 quarters and 5 dimes
2 quarters, 4 dimes and 2 nickels
etc. etc. so there are a lot more combinations.

Answer 2

it won't be able to be achieved. start up with one hundred pennies. you're $4.00 short. a thank you to extend it? protecting the coin count huge style at one hundred, there are six distinctive procedures you may replace 5 pennies into 5 different funds (rather worth 50c, 65c, 80c, 95c, $one million.10 or $one million.25) giving an improve in fee of 45c, 60c, 75c, 90c, $one million.05 or $one million.20. The will improve you % between those might desire to upload as much as $4.00. yet . . . each and every improve you may % is a assorted of three, so the sum of any of them would be a assorted of three, and the finished improve you require isn't a assorted of three. So it won't be able to be achieved. I even have additionally achieved this interior the acceptable mathematical way with 2 simultaneous linear Diophantine equations in 3 unknowns (wow!) and it includes the comparable element - an equation the place one area is a assorted of three and the different one isn't, so there is not any integer answer.

Answer 3

Assuming you are not allowed to use denominations that are no longer legal tender (such as 2 cent pieces, half cents, etc):

10 nickels, 5 dimes
10 pennies, 3 quarters, 1 dime, 1 nickel
5 pennies, 1 nickel, 9 dimes