Significant Digits/ Equilibrium problem, Im not sure if im doing this right?

Question

For the reaction below, Kc = 0.534 at 700 degrees Celsius. A mixture of 0.250 moles of CO and 0.450 moles of H20 are heated to 700 degrees Celsius in a 10.0 L container. Calculate the concentrations of all four species when equilibirium is reached.

H2 + CO2 ---> H20 + CO

okay plz check my answer and do it and see if you get the same if you can. Also I think the significat figs are right...but not sure

first I got the Molarity of CO - .250 moles/10L = .025M and
H20 .450 moles/10L = .045 M

next I did the ICE method to come up with the problem (.025-x)(.045-x)/x^2=0.534

I work this out to get it equal to 0 and it looks like:
.466x^2-.070x+.0011=0

should be be .001125?

I use the solve function on my calculator, And this gives me x=.018 so, if everything is correct then the concentrations should be:

CO = .025-.0183 = .007
H20 = .045-.0183 = .027
H2 =.018
CO2 = .018

How does this look? Just want to know that im doing this right...Im not sure if x should be .018 or .0183 Thanks!

Im pretty sure everything is right, but there might be a couple of sigs wrong, .0183 for x would be more correct if I go back and plug it in for x the answer is more correct, but im not sure I should use it or not. And someone said I should use .001125 instead of .0011, Im not so sure cuz .045 x .025 = 2 sigs so the answer should be to 2 sigs which would be .0011 right?

Answer 1

The value 0.018 has two significnat digits; the value 0.0183 has three. (Zeros leading a number don't count as significant.)

Don't round off any values while doing a calculation until you get to a final answer. You need at least three sig digs in each value in your quadratic : 0.466x^2 - 0.0700 x + 0.001125

When I solved the quadratic, I got x = 0.0183 (3 sig digs).

You can always check your values - put your equilibrium concentration values into the Keq expression - it will work out to the Keq value if your concentrations are correct.

Answer 2

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