Ok so I have the answer and the work done for this question I would just like to verify the answer...
[E] = Sigma Symbol
50
[E] 8(0.5)^(n-2)
n=1
Hope that is clear enough. The answer I have is 16, but the first time I did It I came up with 32. so if anyone could help that would be awesome!
2006-10-15 12:00:01 · 5 answers · asked by gg 4 in Education & Reference ➔ Homework Help
The first term of the sequence underlying this series is 16, because 8(.5)^-1 = 8*2 = 16. so the answer can't possibly be 16. (A trick in the question is that there's "n - 2" rather than "n - 1" in the exponent.)
The common ratio is .5 . The formula S=a(1-r^n)/(1-r) can be used to find the sum of "n" terms of a geometric sequence.
You'd have S = 16(1 - .5^50)/(1-.5) . This is just less than 32 and would converge to 32 for infinitely many terms.
The series is 16 + 8 + 4 + 2 + 1 + .5 + .25 + .125 + ... (to fifty terms).
2006-10-15 13:44:51 · answer #1 · answered by dmb 5 · 0⤊ 0⤋
I understand the equation, but unfortunately I can't remember the trick to solving it. However, given that your last n=50 has a solution of around (2.84 e (-14)), I would probably go with 16 rather than 32.
Sorry I can't be more help.
2006-10-15 12:12:28 · answer #2 · answered by Kwa Nini Hufahamu? 4 · 0⤊ 0⤋
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2016-11-23 13:30:25 · answer #3 · answered by Anonymous · 0⤊ 0⤋
16 this is one half to the one half power times 8
2006-10-15 12:07:07 · answer #4 · answered by bob_whelan1944 3 · 1⤊ 0⤋
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2006-10-15 12:02:06 · answer #5 · answered by ash 4 · 0⤊ 1⤋