How can I calculate the circular speed in a spaceship to get the earths gravity & effects in mentioned ship ?

Question

Imagine that I´m in space lab, moving arount earths orbit but I would like to have this space lab making spins / turns arount itself and get the earths gravity.

Answer 1

The centripetal force exerted on an object to produce angular motion is given by F = mv^2/r. Using this formula, you should be able to calculate what you need, as follows:

When you lay out the dimensions for the portion of the spaceship that will rotate, you can determine the value of r (i.e., the distance from the center of rotation to the location where you want to replicate the force of gravity).

You want the force of "gravity" to be equal to 9.8 N per kg, so the above equation can be manipulated as follows:
F / m = v^2 / r
To achieve "gravity" of 9.8 N per kg, we need to have F / m = 9.8.
So v^2 / r = 9.8 m/s^2

Knowing that v^2 / r = 9.8, you can plug in the value of r in meters (as discussed above) and solve for v (in meters per second).

Then, if you want to convert from a linear velocity (in m/s) to a rotational velocity (in radians per second), divide v by r. If you then want to convert to revolutions per second, divide the radians per second by 2*pi. And if you want to convert revolutions per second to rpm, multiply by 60.

Hope that gives you what you need.

Answer 2

properly, its bodily no longer conceivable to flow faster than the speed of sunshine, it is going into all this extraordinary Einstein stuff about at the same time as ur happening the speed of sunshine, time somewhat slows down, an how right away are u truly going? its very unusual stuff, u can somewhat shuttle on the speed of sunshine in an orbital trajectory, an u'll come decrease back after 5 years, and ten years have handed off in the international. ok properly besides, if a spaceship hit the earth on the speed of sunshine, it wud professional ably make a large crator, or explosion reckoning on the desity and length of the deliver. an extreamly small meteorite may reason large damage and hugde crators, imagine throwing a peddble in a bucket of water, the pebble is small, notwithstanding the the vibrations splash the water out of the bucket. its type of like that. for sure the deliver wud probable really crumple in the ambience, it migth even blow up before it receives to earth, im no longer particular ?

Answer 3

suppose he space lab has a radius of 20m
then mv^2/R = mg
or g = v^2/R = R^2w^2/R = wR
where w is called omega the angular velocity
Put g = 9.8m/s^2 and R = 20m
we get w^2 = g/R 9.8/20 =0.49
Hence w = sqrt(0.49) = 0.7 rad/s

Answer 4

Try http://www.studyphysics.ca/20/unit2/circle/force/note.htm