3.5 moles of Fe2O3 is equivalent to __________ grams of Fe2O3.?

Question

Thanks for the help on the last one. I need just a little more. Can someone give me the formula and the steps to solve this.

Thanks so much for the help :)

Answer 1

basically use the atomic mass number of Fe2O3 so 2 Fe and 3 O so thats O=16 x 3 = 48 and Fe= 55.8 x 2 = 111.6 add them together you get the total mass of Fe2O3 = 159.6 now that per one mole so just times the 159.6 by 3.5 to get 558.6g

Answer 2

well first you need to figure out the molar mass for both iron and oxygen. iron is 55.85 g/mol, and oxygen is 16.00 g/mol. since there are two iron atoms, multiply 55.85 by 2. there are three oxygen atoms, so multiply 16.00 by 3. the answers are 111.7 and 48.00, respectively. add them up together and the answer is 159.7. then multiply that by 3.5, since you need three and a half moles. the answer is 558.95. and you need to take the significant digits into account, which I /think/ would make it 560 grams.

*edit* it seems that the other people replying to this topic are giving different results. it all depends on what your periodic table gives for the mass of the elements. some round the numbers, some don't.

Answer 3

1 mole Fe2O3 = (56*2) + (16*3)
= 160 grams

1 mole Fe2O3 = 160 g
3.5 moles Fe2O3 = x
THEN CROSS MULTIPLY

3.5 * 160 = X
X = 560 grams

Answer 4

2 moles of Fe at 55.85g/mol = 111.7 grams
3 moles of O at 16g/mol = 48 grams
111.7+48 = 159.7 grams in one mole of Fe2O3.
159.7 * 3 = 479.1 grams in 3 moles of Fe2O3.

Sorry...you need to multiply by 3.5
558.95

Answer 5

Okay so i think the answer is 558.6 grams. Im sorry if im wrong!