still can't solve it. Here it is: (x-4)(x+4x+16)....
I get (x-4)(5x+16)..where do I go from here?
Thanks
2006-10-15 09:13:31 · 5 answers · asked by bobbysgirlmeri 2 in Science & Mathematics ➔ Mathematics
(x - 4)(x + 4x + 16)
(x - 4) (5x + 16)- - - Collecting like terms
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FOIL Method
(x - 4)(5x + 16) =
5x² + 16x - 20x - 64 =
5x² - 4x - 64
- - - - - - - - - - - - -s
2006-10-15 09:32:01 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
what do you want out of this problem, i dont understand.
However, let me continue with the multiplication.
(x - 4) (x + 4x + 16)
= x(x + 4x + 16) - 4(x + 4x + 16)
= x(5x + 16) - 4(5x + 16)
= 5x^2 + 16x - 20x - 64
= 5x^2 - 4x - 64
= 5x^2 - 20x + 16x - 64
= 5x(x - 4) + 16(x - 4)
= (5x +16)(x - 4)
2006-10-15 09:18:16 · answer #2 · answered by aazib_1 3 · 0⤊ 0⤋
(x-4)(x+4x+16)
(x-4)(5x+16)
Use the FOIL method.
Multiply the "F"irst terms: x(5x) = 5x^2
Multiply the "O"uter terms: x(16) = 16x
Multiply the "I"nner terms: -4(5x) = -20x
Multiply the "L"ast terms: -4(16) = -64
Combine terms:
5x^2+16x-20x-64
And you get:
5x^2-4x-64
Regards,
Mysstere
2006-10-15 09:18:57 · answer #3 · answered by mysstere 5 · 0⤊ 0⤋
(x-4)(x+4x+16)
(x-4)(5x+16) so far so good
now use FOIL- 1st terms, outside terms, inside terms last terms
5x^2+16x-20x-80
5x^2-4x-80
Unless there is a typo & it should be
(x-4)(x^2+4x+16) in which case you shoud get
x^3+4x^2+16x
-4x^2-16x-64
x^3-64
2006-10-15 09:24:47 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
I think , 5x squared + 16x - 20x - 64
5x sq - 4x -64 > > maybe ?
2006-10-15 09:24:12 · answer #5 · answered by kate 7 · 0⤊ 0⤋