HELP I need 2
2006-10-15 08:42:15 · 9 answers · asked by whatever 1 in Science & Mathematics ➔ Mathematics
44 and 66 is the most obvious answer but there are infinitely many others.
44 and 110 (2 x 22 and 5 x 22)
66 and 110 (3 x 22 and 5 x 22)
66 and 154 (3 x 22 and 7 x 22)
110 and 154 (5 x 22 and 7 x 22)
66 and 242 (3 x 22 and 11 x 22)
just choose two different prime numbers and multiply 22 by each of them.
or indeed choose n different prime numbers and multiply 22 by each of them.
As they are all prime, they will have no common factor and so the GCF cannot be more than 22,
2006-10-15 09:48:28 · answer #1 · answered by Anonymous · 6⤊ 0⤋
GCF = greatest common factor? If so, then your 2 answers need to be greater than 22, not less (like the first two answerers gave you)
To get your answer, consider 22 * a, where a is a number that has neither 2 nor 11 as its multiple.
Hope this was enough information to get you to thinking about the problem so you could solve the rest of it yourself!
Good luck kid!
2006-10-15 08:46:48 · answer #2 · answered by I ♥ AUG 6 · 0⤊ 0⤋
44 22
2006-10-15 08:54:08 · answer #3 · answered by lemon drops 3 · 0⤊ 0⤋
44 and 66.
The factors of 44 are 1, 2, 4, 11, 22, and 44
The factors of 66 are 1, 2, 3, 6, 11, 22, 33, and 66
2006-10-15 08:50:33 · answer #4 · answered by cubs_woo_cubs_woo 3 · 0⤊ 1⤋
How about 44 and 66?
2006-10-15 10:33:07 · answer #5 · answered by steiner1745 7 · 0⤊ 0⤋
If there are no common prime factors, the GCF is 1.
2006-10-15 08:51:13 · answer #6 · answered by lookinsavannahtn 1 · 0⤊ 1⤋
Any mulitiple of 22
2006-10-15 08:59:49 · answer #7 · answered by Anonymous · 0⤊ 1⤋
1 and 22
OR
2 and 11
I'm assuming you mean integers, without a fraction or decimal.
2006-10-15 08:45:15 · answer #8 · answered by Squeaky 2 · 0⤊ 1⤋
1,2,11,22
2006-10-15 08:44:09 · answer #9 · answered by natasha(; 2 · 0⤊ 1⤋