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can somebody explain how to sketch a pair of lines and tell whether they are parrellel, perpendicular, or niether and this is the problem:
y=5x-4
x=2

what do i do??? someone please help i don';t understand slope either i know that it's y=mx+b butthen i don't get what to do!!!!!!!!!

thanks!!!!!!

2006-10-15 08:29:03 · 4 answers · asked by molly 2 in Education & Reference Homework Help

4 answers

Since it says "sketch" the lines, you need to graph them. If they are parallel, they'd go side-by-side, never intersecting. If they are perpendicular, they'll make a right angle. If they're neither, they'll intersect, but not at a right angle.

To graph y = 5x - 4, you start by finding the y-intercept (the "b" in y = mx + b), which here is -4. That means you start by making a point on the y-axis 4 below the origin. Then you find the slope (the "m", which here is 5 or 5/1). From the point you just made, count up 5 and over (to the right) 1, and make another point. You connect those to make your line.

The "y = mx + b" rule breaks down when you don't have a "y", so you just have to remember that lines that have the form "x = #" are vertical lines. To graph x = 2, you count to the right 2 from the origin. You then make a vertical (up and down) line through there.

These two lines will intersect, but not at a right angle, so this one is "neither".

2006-10-15 08:42:31 · answer #1 · answered by dmb 5 · 2 0

if you can get the equation of a line into the form y=mx+b
then you're nearly there. the value of m is the slope of that line.
two lines are parallel if they have the same slope
two lines are perpendicular if the slope of one is the negative reciprocal of the other, that is if m1 is the slope of one line and m2 is the slope of the other, they are perpendicular if m1 = -1/m2

you gave us:
y = 5x-4 slope is 5
x=2 in this case x is always 2 and y can have any value which is just a vertical line at x=2, this has an infinite slope (a horizontal line has a slope of zero, this would be one where x is not in the equation such as y=3, y is 3 for all values of x)

so when we compare the slopes (5 versus infinity) we
see that they are not the same (lines are not parallel)
and one is not the negative reciprocal of the other (not
perpendicular)

so you don't really need to sketch the lines to make
the determination.

2006-10-15 15:39:46 · answer #2 · answered by T M 6 · 0 1

If it was perpendicular it would have the reciprocal of the slope...so one would have a slope of 3/2 and the other would have a slope of 2/3... parrallel means both lines have the same slope but different intercepts...

x=2 means there is a vertical line at x=2, and the slope is undefined

In the case of y=5x-4, the slope is 5/1

This means that the lines are not perpendicular or parrallel... you can plug in x=2 for y=5(2)-4=6...so basically the two lines intersect at (2,6)

hope this helps

2006-10-15 15:35:42 · answer #3 · answered by Some Dude 1 · 0 0

if it's parallel (II) x=2 will stay the same. Just plug in 2 to the equation and you have your parallel line.

parallel: y=5(2)-4
y=10-4
y (parallel)=6

perpendicular (T) the value of x (2) has to become the negative reciprocal

x will equal -1/2 all you have to do is make it negative and put a one over it.
Plug -1/2 into the equation

y=5(-1/2)-4
y=2.5-4
y (perpendicular)= -1.5

They're parallel because they never intersect. You'll see once you sketch these. Hope this helps

2006-10-15 15:37:10 · answer #4 · answered by Alyssa 1 · 0 1

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