Please help me do this please!?

Question

1. Picture a triangle if u will. on the left side is a 6, on the right side is an a and the base is 6. the other triangle if u will: a b on the left side, a 2 on the right side, and a 1 on the base. how would i set up each side to find a and b? please help me


2. Picture two more triangles. an a on the left side, a b on the right side, and a 4 at the base. On the other one: a 3 at the top, a 5 on the left side and a 4 on the right side. How do I set up to find a and b? please help me

3. Picture a sideways triangle. 3/2 on the left, 3 in the bottom right and b at the top right. Picture another one turned the opposite direction. a 1 on the top, 1/2 on the left, and 1/2 on the right. how do i set up to find b? help

4. Picture a triangle with an a on the left, 34 on the right and 16 at the bottom. On the other, at 8 at the top, a c on the left, and 15 on the right. how do i set up to find A and C?

1. There is one angle mark at the bottom left, and one angle mark at the bottom right. same for the other triangle.

2. there is 1 angle mark at the top and a 90 angle symbol at the bottom left. in the other triangle there is a right angle mark up b/w the 3 and 4, and an angle mark at the bottom below the 4 and 5.

3. there are 2 angle marks at the top and one angle mark at the bottom left. in the other triangle, there are 2 angle marks at the bottom left and one at the bottom right.

4. there is a right angle mark at the bottom left, and an angle mark at the bottom right. in the other 1 is a right angle mark at the bottom right b/w the 8 and 15, and an angle mark between the 8 and c at the other side.

Answer 1

Unfortunately, without any angles, we cannot determine the sides.

For instance, in your first question, the first triangle. I understand that one side and the base are both 6. The other side could be really short or long as in an isosceles triangle, or it could be 6 as in an equilateral triangle. Do you have any more information??

Regards,

Mysstere

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The best I can do from your extra information is the following:

1) Deals with isosceles triangles. This means that since the angles at the base are the same, the sides will be the same. Since they have given you a triangle where both one side and base are the same, then it is actually an equilateral triangle and "a" will equal 6. In the second triangle, the angles are the same, so the side will be the same. b=2

2) I believe these are both right triangles. Pythagoream theorem is a^2+b^2 = c^2, where c^2 is the hypotenuse. Since they already gave you a 3,4,5 right triangle (on the right) the left is the same with base of 4. So, a and b are also 3 and 5.

3) This problem already seems to have one triangle solved. It has sides of 1/2 and a base of 1. Another isosceles triangle. Since 3/2 is 3 times 1/2, and 3 is 3 times 1, then the b will be 3/2 as well.

4) These triangles use the identities you have found above. I believe these are right triangles as well. So:

a^2+b^2 = c^2.

Sides on the right will be 8, 15, and 17--this is a special identity like the 3,4,5 right triangle.

The triangle on the left...solving the equation:

a^2 + 16^2 = 34^2

a = 30

Regards,

Mysstere