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In terms of delta(change in)d and delta(change in)t, acceleration is expressed as....?...


In air, a dense object such as a lead shot falls (slower than, at the same speed as, faster than) .......?.......,an object of lower density, such as a dry tree leaf.

2006-10-15 07:59:45 · 4 answers · asked by dreamz 4 in Science & Mathematics Physics

4 answers

delta delta d over delta t (i think)
delta d over delta t gives u velocity
acceleration is derivative of velocity so it is second derivative of d
i am not sure how to express that in delta form i think itll be like: d(dD)/dt
in second question the lead shotfall faster because it has less surface area due to greater density and thus air resistance is much less, proportionally to mass and thus it will not be slowed down as much by air so fall faster

2006-10-15 08:05:11 · answer #1 · answered by smart son of a bich 2 · 0 0

a = delta v/delta t, v = delta d/delta t, so
a = delta^2 d/(delta t)^2, where
^2 means perform the operation twice

Faster, although you may have to use considerable height to demonstrate it. That's what makes parachutes possible. The greater the surface area, the slower the fall.

2006-10-15 08:14:40 · answer #2 · answered by Helmut 7 · 0 0

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2016-10-19 10:53:25 · answer #3 · answered by agudelo 4 · 0 0

i dont know the first one but the second one is faster than

2006-10-15 08:02:46 · answer #4 · answered by Bugalachoo 2 · 0 0

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