Help With This Riddle!!?

Question

A farmer had his own collection of zoo animals. When a census asked him how many birds and how many cows he had the farmer replied:

" Well I have 36 heads and 100 feet altogether"

The census takers had to figure out how many of each animal the famer had.

How many birds and how many cows were their?

Answer 1

To solve this, we set up a system of linear equations:

We know that there are 36 heads in total, and each animal has one head, therefore the number of cows (c) and the number of birds (b) add up to 36:

b+c=36

we also know that each cow has 4 feet, and each bird has 2. Therefore the number of feet from cows (4c) and the number of feet from birds (2c) add up to 100:

2b+4c=100

we solve these two equations:

2b+4c=100
-2(b+c)=-2(36)
2c=28
or c=14

b+c=b+14=36, so b=22.

There are 22 birds and 14 cows.

Answer 2

There are 22 birds and 14 cows = 36 heads, 22b=44 feet and 14c=56, and 44+56 = 100 feet. So there are 2 feets and 4 feets. 36 heads, so put in 24 for 2 feet and 12 for 4 feet and it is near the answer. This is a guess and check type of riddle.

Answer 3

22 birds and 14 cows

Answer 4

14 cows and 22 birds

Answer 5

20 birds 16 cows

Answer 6

14 birds and 18 cows

Answer 7

14 cows, 22 birds

Answer 8

let x = birds
and y = cows
x + y = 36
2x + 4y = 100
y = 50 - 36 = 14
x = 36 - 14 = 22

Check:
2*22 + 4*14 = 44 + 56 = 100

Answer 9

Let us assume x be the no. of animals and
y be the no. of birds. We have the equations
4x+2y=100....1
x+y=36
2x+2y=72.......2
from 1&2
2x=28
x=14
y=22
verify
14*4+2*22
=56+44=100
ok

Answer 10

let number of birds be b
no. of cows be c
each has one head only:so
c +b =36
and one bird has 2 ft and one cow has 4 ft
so
2b + 4c = 100
solve the two simultaneous equations
c = 56
b = 22