A particle of mass 4 kg is pulled to the top of a cylindrical surface of radius 1 m using a cord at a constant speed, as shown in the figure (see link)
https://tycho-s.physics.wisc.edu/cgi/courses/shell/common/showme.pl?courses/phys201/fall06/homework/06/particle/cylinder.jpg
Assuming that the contact is frictionless, what is the force at angle of 57 degrees?
2006-10-15 06:28:39 · 1 answers · asked by Stacy K 2 in Education & Reference ➔ Homework Help
Since the velocity is constant, the force is the weight of the object not supported by the cylinder.
If you draw a line vertically through the mass at the point of contact with the cylinder, that will form the hypotenuse of a right triangle with one side as the tangent on the cylinder at the point of contac. The angle of the tangent to the hypotenuse is 57 degrees.
the weight of the object is m*g
the part not supported by the cylinder is
cos(57)*4*9.8 N
=21.34 N
You can check the correctness by evaluating cos(0) = 1
and cos (90)=0
j
2006-10-16 13:08:57 · answer #1 · answered by odu83 7 · 0⤊ 0⤋