Please show me how you do this problem?

Question

The distance, d (in meters), travelled by a falling object is given by the equation d=4.9t^2, where t i the time in seconds. From what height was the object originally dropped if it took 4.24 seconds to hit the ground? Round answers to the nearest whole number.

Answer 1

You're kidding right? They give you the formula: just put the time into it and simplify. Honestly, this is like that old tech support horror story about someone asking "If the dialog box says I should click OK to continue, does that mean I should click OK to continue?"

Answer 2

Don't be scared of formulae, it's all very simple really. Just put your value of t in your formula to get the corresponding value of d. If you are wondering why 4.9 appears there, it's because more generally the distance a uniformly accelerating object travels in a given time is half of the acceleration times the square of the time (and why is that? you need a bit of calculus to go there, it's not hard but that's for later). In the special case of a falling object, it accelerates at g, the acceleration due to the gravity of the earth, which is approximately 9.8 metres per second per second (that just happens to be what it is on Earth, on the moon or on Mars it would be different because they have different masses). Half of g is 4.9.

Answer 3

substitute in t=4.24s into the equation. you will get a value for d, which is the distance travelled....which also means from which height is e object dropped

Answer 4

we are trying to get the distance d

by using the acceleration formula a=d/t^2, we know that we are in a planet that has roughly half of earth's gravitational force

the rest is easy, following the formula and substituting:

d = 4.9 * (4.24^2)

d = 4.9 * 18

d= 88.2

Answer 5

d=4.9t^2 i didn't get this ...

Answer 6

d=4.9(4.24)^2
d=? (calculate and you are done)