a gas has a volume of 10 L at 50degrees C and 200 mm Hg pressure. What correction factor is needed to give a volume at STP?
i dont know how to approach this. I dont understand what the correction factor is.
it uses the van der waals equation, which is
[P+a(n/V)^2]* (V-nb)=nRT
its a variation of the ideal gas law but idk what to do!
any help is greatly appreciated.
THANKS! :)
2006-10-15 05:02:10 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
From the Ideal Gas Law,
PV = nRT
nR = P1V1/T1 = P2V2/T2
V2/V1 = (T2/T1)(P1/P2)
V2 = 10 L((50+273)/20+273))(200 mm/760 mm)
V2 = (10)(323/293)(200/760) L
V2 = 2.901 L
Using your equation,
nR = [P1 + a(nV1)^2](V1-nb)/T1
nR = [P2 + a(nV2)^2](V2-nb)/T2
You can manipulate these further, but you must now know n, a, and b to solve.
2006-10-15 05:21:02 · answer #1 · answered by Helmut 7 · 1⤊ 0⤋
I AM VERY CERTAIN THAT THE ANSWER TO THIS QUESTION IS 10.08....I AM IN SUCH A HURRY TO EXPLAIN THE DETAILS NOW, BUT CONVERT UR PRESSURE TO ATMOSPHERE AND ASSUME THAT N=1, SSOLVE FOR -R(MOLAR GAS CONSTANT). THEN U'LL GET SOME 8.14E-3. DIVIDE THE REAL MOLARE GAS CONSTANT 0.08206 BY THIS 8.14E-3, AND UGET 10.08, THAT IS THE CORRECTION FACTOR TO GIVE A VOLUME AT STP.
U COULD ALSO , USE Dr. j's BUT REMEBER TO DIVIDE THE VOLUMES TO FIND THE RATIO. AND THAT WILL BE THE FACTOR
HOPE THIS HELPS
2006-10-15 05:22:48 · answer #2 · answered by Anonymous · 1⤊ 0⤋
If you can assume that your gas is ideal then
P1V1/T1 = P2V2/T2
You have P1,V1,T1. Use STP conditions and you have P2, T2. Substitute in equation to get V2.
2006-10-15 05:14:06 · answer #3 · answered by Dr. J. 6 · 1⤊ 0⤋
the gas law is called the 20 second rule. leave the room break wind wait 20 seconds return
2006-10-15 05:05:03 · answer #4 · answered by boss4292006 2 · 0⤊ 3⤋