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Can anyone tell me how to prove that :
P(A)+P(B)-1 <= P(A intersect B)

2006-10-15 02:20:06 · 2 answers · asked by homeboy187nic 2 in Science & Mathematics Mathematics

2 answers

Switch this so it says P(A)+P(B)-P(A int. B)<=1.

The left side of the equation is equivalent to A union B, which has a maximal probability of 1.

2006-10-15 02:41:09 · answer #1 · answered by zex20913 5 · 0 0

You know that:

P(A union B) <= 1

You also know that:

P( A union B ) = P(A) + P(B) - P(A intersect B)

Thus,

P(A) + P(B) - P(A intersect B) <= 1

Add P(A intersect B) to both sides and subtract 1 from both sides. The result:

P(A) + P(B) - 1 <= P(A intersect B)

2006-10-15 09:36:28 · answer #2 · answered by Ted 4 · 0 0

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