2006-10-15 02:17:23 · 9 answers · asked by Gerry K 2 in Education & Reference ➔ Primary & Secondary Education
Change the signs inside the () because of the '-'
3x - [6x-3x-3] - 2
Then, change the signs inside the [] because of the '-'
3x - 6x +3x +3 -2
Combine like terms
3x - 6x -3x = 0 and 3-2 = 1
You are left with 1
2006-10-15 02:21:11 · answer #1 · answered by just browsin 6 · 0⤊ 0⤋
expand the equation. This means do the operations to get rid of the brackets.
Your equuation will then look like this:
=3x-[6x-3x-3]-2
=3x-6x+3x+3-2
=1
2006-10-15 02:19:01 · answer #2 · answered by Scarlet Element 2 · 0⤊ 0⤋
First off expand all those silly brackets
3x - [6x -(3x + 3)] -2
3x - [6x -3x -3] -2
3x - 6x + 3x +3 -2
then add it up all the x's cancel out and you're left with 1
(you sure you type it right?)
2006-10-15 02:20:59 · answer #3 · answered by rchlbsxy2 5 · 0⤊ 0⤋
First, you work from the innermost bracket.
3x - [6x-(3x + 3)]-2 remember that brackets mean multiply
= 3x - [6x-3x - 3] -2 when you multiply minus with plus, you get = 3x - 3x +3 -2 negative number. When minus multiply
= 1 minus, it gives you positive number.
2006-10-15 02:48:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I would give the X a value of 1. then the problem becomes 3(1)-(6(1)-(3(1)+3)-2 do the part of the problem that is in brackets 1st which is 6-(3+3) which cancels out so then problem becomes 3-2 which equals 1.(my computer keyboard does not have a bracker key)
2006-10-15 02:37:06 · answer #5 · answered by bettyswestbrook 4 · 0⤊ 0⤋
3x-{6x-(3x+3)}-2 =3x-{6x-3x-3)-2 =3x-6x+3x+3-2 =6x-6x+1 =1 Ans
2006-10-15 05:02:41 · answer #6 · answered by alpha 7 · 0⤊ 0⤋
3x - [6x -(3x+3)] -2
3x - [6x -3x -3] - 2
3x - [3x-3] - 2
3x -3x + 3 -2
1
2006-10-15 02:27:36 · answer #7 · answered by Payam Samidoost 2 · 0⤊ 0⤋
3x-[3x-3]-2
3x-3x+3-2
3-2
1
2006-10-15 04:12:53 · answer #8 · answered by ? 5 · 0⤊ 0⤋
3x [18x^2+18x] -2
=54x^3+54x^2-2
=2(27x^3+54x^2-1).......i think......
2006-10-15 02:24:39 · answer #9 · answered by MrSmarT 3 · 1⤊ 1⤋